EXAM+Information+and+Discussion

Chemistry Exam *List of Topics May 2010 18. Heat Equation – Chapter 13 – Heating, cooling curve, 5 step problem, 19. Compare activation energy of endothermic and exothermic reactions (foldable)
 * 1) Write and balance equations from a word problem. You must review chemical nomenclature of the three types of compounds and be able to use the periodic chart to write correct chemical formulas. Identify the type of chemical reaction.
 * 2) Example problems: #16, 17, 20 page 208
 * 1) Write molecular equations, complete ionic equations, and net ionic equations. Example problem Self Check 7.2 on page 185.
 * 1) SIGNIFICANT FIGURES:
 * 2) Perform calculations with correct significant figures. Self Check 2.3, page 28
 * 1) Classify elements in the periodic table; Figure 10.35, page 304; Remember Boron is considered a metalloid in most texts.
 * 1) Memorize names, formulas, charges of polyatomic ions.
 * 1)  Calculate molecular formulas from empirical formulas. Example: #78, page 242;
 * 2) Self check 8.11, page 236
 * 1) Calculate empirical formula from % composition.
 * 2) Example: # 17, page 277; Self check 8.9, page 234
 * 1) Perform calculations to determine mass or moles of products when given mass or moles of reactants. Be able to calculate molar mass of compounds, including hydrates. Example #50, page 272
 * 1) Perform calculations to determine the limiting reagent of a reaction. Example #46, page 271; self check 9.6 page 264
 * 1) Determine % yield of reaction. Example # 62, page 273; self check 9.7 page 266
 * 1) Predict bond type based on electronegativity difference of atoms in a bond. Problem #14, page 350.
 * 1) Assign intermolecular forces to molecules based on polarity. Rank intermolecular forces in terms of strength. Problems 25 & 26 page 418
 * 1) Gas laws – Chapter 12 – and Kinetic Molecular Theory, page 383, work one problem example of each gas law, including Ideal Gas Law. What is STP?
 * 1) Solution chemistry – Chapter 14 – Identify solute, solvent, Interpret solubility curve, % composition, molarity, dilution, and neutralization calculations.
 * 1) Acid/Base chemistry – Chapter 15 - Identify equivalence point on a titration curve. Write neutralization equations. Determine the reactants required to produce a given salt in a neutralization equation.
 * 1) Calculate pH, pOH, Kw, [H+], [OH-] – Identify lab equipment for titration.

Vocabulary List Ch 2, 3, 5, 6, 7, 11, 12, 13, 14, 15, 17, 18


 * 1) Conversion factor
 * 2) Celsius scale
 * 3) Kelvin
 * 4) heat
 * 5) distillation
 * 6) filtration
 * 7) calorie
 * 8) joule
 * 9) exothermic
 * 10) endothermic
 * 11) activation energy
 * 12) Precipitate
 * 13) Strong electrolyte
 * 14) Insoluble
 * 15) Spectator ions
 * 16) Net ionic equation
 * 17) Combustion
 * 18) Oxidation-reduction
 * 19) Decomposition
 * 20) Double-displacement
 * 21) Complete ionic equation
 * 22) Bond
 * 23) Ionic bond
 * 24) Covalent bond
 * 25) Polar covalent bond
 * 26) Electronegativity
 * 27) Dipole moment
 * 28) Lewis structure
 * 29) Duet rule
 * 30) Octet rule
 * 31) Absolute zero
 * 32) Molar volume of a gas
 * 33) Standard temperature and pressure
 * 34) Intramolecular forces
 * 35) Intermolecular forces
 * 36) Solvent
 * 37) Solute
 * 38) Saturated
 * 39) Unsaturated
 * 40) Concentrated
 * 41) Dilute
 * 42) Molarity
 * 43) Molality
 * 44) Dilution
 * 45) pH
 * 46) Hydronium ion
 * 47) pOH
 * 48) half-life
 * 49) radiotracer
 * 50) fission
 * 51) fusion
 * 52) isotope
 * 53) corrosion
 * 54) electrolysis
 * 55) extrapolation
 * 56) interpolation
 * 57) continuous data
 * 58) discrete data
 * 59) independent variable
 * 60) dependent variable
 * 61) frequency distribution

// Exam Formulas // // May 2010 // PV = nRT

R = 0.08206 L atm/mol K

K = oC + 273

V1P1 = V2 P2

V1/T1 = V2/T2

PT = P1 + P2 + P 3 …

1 atm = 760 torr

760 mm = 760 torr

M1V1 = M2V2

Qfus = mol x Δ Hfus

Qvap = mol x Δ Hvap

Q = mc Δ T c (ice) = 2.06 J/g oC

c (liquid water) = 4.184 J/g oC

c (water vapor) = 2.02 J/g oC

Δ Hfus = 6.02 kJ/mol (water)

Δ Hvap = 40.7 kJ/mol (water)

M = moles of solute / Liter of solution

MaVa = MbVb

pH + pOH = 14 Kw = [H+] [OH-]

pH = - log [H+] pOH = - log [OH-]